Find the length of AD
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H^2=P^2+B^2 H=AC=10cm P=AD=? B=CD=26/2=13 Putting these value in pythagoras theorem=AC^2=AD^2+CD^2 =(10)^2=AD^2+(13)^2 =100=AD^2+169 =169-100=AD^2 AD^2=69 AD=√69 AD=3√13cm
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It is a parallelogram therefore opposite sides are equal
ie, AB = CD = 16 cm
Area of parallelogram = bh
Area = CD×AE = 16×8 = 128 cm²
Now CF is the height and AD is the base
Area = CF×AD
128 = 10×AD
AD = 128/10 = 12.8 cm
AD = 12.8 cm
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