Question

Find the length of altitude to the smallest side of a triangle having sides of lengths 7cm,5cm
and 8cm.
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Answer 1

Step-by-step explanation:

semi perimeter= (a+b+c)/2

= (7+5+8)/2

= 20/2

= 10

area of ∆= √s(s-a)(s-b)(s-c)

= √10(10-7)(10-5)(10-8)

= √10×3×5×2

= √10×10×3

= 10√3

we know that,

area of ∆= 1/2×b×h

10√3= 1/2×5×h

20√3=5h

4√3= h

#666

Answer 2

4√3 is the answer so kindlya understand what