Question

Find the length of an altitude on the hypotenuse of a right angled triangle of legs of length. 15 feet and 20 feet.

Answer 1

Answer:

Please see the attachment

Answer 2

The length of an altitude on the hypotenuse=12 cm

Step-by-step explanation:

In right triangle ABC

AB=20 ft

BC=15 ft

$AC^2=AB^2+BC^2$

By using Pythagoras theorem

$(Hypotenuse)^2=Base^2+(Perpendicular\;side)^2$

$AC^2=(15)^2+(20)^2$

$AC=225+400=625$

$AC=\sqrt{625}=25cm$

Area of triangle=$\frac{1}{2}\times base\times height$

Area of triangle ABC=$\frac{1}{2}\times BC\times AB=\frac{1}{2}(15)(20)=150cm^2$

Area of triangle ABC=$\frac{1}{2}\times BD\times AC$

$150=\frac{1}{2}\times BC\times 25$

$BD=\frac{150\times 2}{25}=12 cm$

Hence, the length of an altitude on the hypotenuse=12 cm

#Learns more:

https://brainly.in/question/2313184