Question

Find the length of an arc of radius 5 cm subtending a central angle of 15°. plz answer fast​

Answer 1

Let s be the length of the arc subtending an angle θ at the centre of a circle of radius r. Then,

→ θ = s/r

Here,

• r = 5 cm and

• θ = 15°

$= > {(15 \times \frac{\pi}{180}) }^{r} = {( \frac{\pi}{12}) }^{r} \\ \\ = > \theta = \frac{5\pi}{12} cm$

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Answer 2

Let s be the length of the arc subtending an angle θ at the centre of a circle of radius r. Then,

→ θ = s/r

Here,

r = 5 cm and

θ = 15°