Question

find the length of angle bisector of triangle abc where a = 6 CM B = 6 CM C = 6 CM​

Answer 1

6

$1 \frac{11 { {1 {0 \times \frac{?}{?} }^{?} }^{2} }^{?} }{?}$

6 plus

6 plus 12 and 21

Answer 2

Answer:

Length of Angle Bisector = 3√3 cm = 5.19 cm

Step-by-step explanation:

find the length of angle bisector of triangle abc where a = 6 CM B = 6 CM C = 6 CM​

in ΔABC  all sides = 6 cm

so this is an equilateral triangle

Area of Equilateral triangle = √3 / 4 * (Side)²

= (√3 / 4 ) * 6²

= (√3 / 4 ) * 36

= 9 √3

Angle bisector of Equilateral triangle is perpendicular to line it intersect

Area of Triangle = (1/2) * Base * Height

= (1/2) * 6 * Height

= 3 * height

Equating both areas

3 * height =  9 √3

=> height = 3√3 cm

Length of Angle Bisector = 3√3 cm = 5.19 cm