find the length of arc of form a circuit of radius 12cm by a board 12cm long also find the area of minor segment.
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Answer:
=OB=12 cm= radius of the circle and .Let AB be the chord of 12 cm. hence we get an equilateral triangle OAB inside the circle that means ∠O=∠A=∠B=60
o
to find the length of the arcs (APB and ADB) of circle.
circumference of the circle =2πr=2π×12 length of the arc APB of the circle =
360
2π×12×60
=
360
2π×12×60
=4π=12.56 cm
Now the length of the arc AQB=
360
2π×12×(360−60)
=
360
2π×12×300
=20π
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