Question

find the length of BC in the figure​

Answer 1

formulas used

$tan \: x = \frac{perpendicular}{base}$

$tan \: 30 = \frac{1}{ \sqrt{3} }$

$tan \: 45 = 1$

in triangle ADC

Tan 30= AD/DC

1/√3= 60/DC

DC=60√3 m

in triangle ABD

tan 45=AD/BD

1=60/BD

BD=60m

BC=BD+DC

=60+60√3

=60(1+√3)