find the length of canvas required
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Answer:
circumference = 2 x 22/7 x r= 44
=> r=44/22 x 2/7 = 4/7=radius
in case of tent area of base of tent is is counted in whole area of tent,So
=> CSA of tent = length x width(of canvas)
L=√h² + r²
L=10(approx)
=> 22/7 x 4/7 x 10 = length x 2
=> 880/49 x 1/2 = length
=>length = 440/49 or 8.979591
I don't think it is right, may be it is wrong
YashPuri07:
sorry correct ans is
something else
Answered by
0
Answer:
circumference = 2 x 22/7 x r= 44
=> r=44/22 x 2/7 = 4/7=radius
in case of tent area of base of tent is is counted in whole area of tent,So
=> CSA of tent = length x width(of canvas)
L=√h² + r²
L=10(approx)
=> 22/7 x 4/7 x 10 = length x 2
=> 880/49 x 1/2 = length
=>length = 440/49 or 8.979591
Step-by-step explanation:
you just copied my ans but it is wrong
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