find the length of cd
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Hi !
Let BC be "b" .
In Δ DCA ,
tan x° = CD/AC
CD/AC = 5/12
CD/AB+BC = 5/12
CD/48 + b = 5/12
5(48 + b) = 12 CD
CD = 5(48 +b)/12 -----> (1)
In Δ DCB ,
tan y° = CD /BC
CD/BC = 3/4
CD/b = 3/4
3b = 4 CD
CD = 3 b / 4 -----> (2)
Equation (1) = equation (2)
5(48 +b)/12 = 3b/4
Cross multiply ,
36 b = 4*{5(48 + b)}
36 b = 4{ 240 + 5b }
36b = 960 + 20 b
16 b = 960
b = 960/16
b = 60
From eqn(2),
CD = 3b/4
= 3*60/4
= 180/4
= 45 m
Length of CD is 45 m
Let BC be "b" .
In Δ DCA ,
tan x° = CD/AC
CD/AC = 5/12
CD/AB+BC = 5/12
CD/48 + b = 5/12
5(48 + b) = 12 CD
CD = 5(48 +b)/12 -----> (1)
In Δ DCB ,
tan y° = CD /BC
CD/BC = 3/4
CD/b = 3/4
3b = 4 CD
CD = 3 b / 4 -----> (2)
Equation (1) = equation (2)
5(48 +b)/12 = 3b/4
Cross multiply ,
36 b = 4*{5(48 + b)}
36 b = 4{ 240 + 5b }
36b = 960 + 20 b
16 b = 960
b = 960/16
b = 60
From eqn(2),
CD = 3b/4
= 3*60/4
= 180/4
= 45 m
Length of CD is 45 m
Anonymous:
Hope this helps you !
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