Find the length of chord whose distance from the center is 4 cm and radius is 5 cm.
Answers
Answered by
2
=>( 5 + 5 ) - (4+4)
=> 10 - 8
=> 2cm
- hope this helps!!
Answered by
1
Using pythagoras theorem,
h^2 = p^2 + b^2
Or, b^2 = h^2 - p^2
Or, b = root under h^2 - b^2
b = root under 5^2 - 4^2
= root under 25 - 16
= root under 9
= 3 cm
Now,
Length of chord = 2 * 3 cm
= 6 cm
Hope it helps
h^2 = p^2 + b^2
Or, b^2 = h^2 - p^2
Or, b = root under h^2 - b^2
b = root under 5^2 - 4^2
= root under 25 - 16
= root under 9
= 3 cm
Now,
Length of chord = 2 * 3 cm
= 6 cm
Hope it helps
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