Question

Find the length of diagonal of a cuboid of dimentions 0.3cm × 4cm × 5cm​

Answer 1

Answer:

$diagonal \: of \: a \: cuboid \: \\ = \sqrt{l {}^{2} + b {}^{2} + h {}^{2} } \\ = \sqrt{(0.3 ){}^{2} + 4 {}^{2} + 5 {}^{2} } \\ = \sqrt{0.09 + 16 + 25} \\ = \sqrt{41.09} \\ = 6.4101482042$

Answer 2

Given : a cuboid of dimensions 0.3cm × 4cm × 5cm​

To find : length of diagonal of  cuboid

Solution:

Diagonal of a cuboid  = √length² + Breadth² + height²

cuboid of dimensions 0.3cm × 4cm × 5cm​

Length =  5 cm

Breadth = 4 cm

Height = 0.3 cm

Hence Diagonal of  cuboid = √5² + 4² + (0.3)²

= √(25 + 16 + 0.09)

= √41.09

= 6.41 cm

length of diagonal of a cuboid of dimensions 0.3cm × 4cm × 5cm​ = 6.41 cm

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