Question

find the length of diagonal of a rectangle whose length 2m.breath1.5

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$let \: abcd \: be \: a \: rectangle \\ ab = 1.5m \\ bc = 2m$
In ΔABC,

Angle ABC=90°..............(ANGLE OF A RECTANGLE)

$by \: pythagoras \: theorem \\ {AC}^{2} = {AB}^{2} + {BC}^{2} \\ {AC}^{2} = {1.5}^{2} + {2}^{2} \\ {AC}^{2} = 2.25 + 4 \\ {AC}^{2} = 6.25 \\ \sqrt{ {AC}^{2} } = \sqrt{6.25}........(taking \: squae \: roots \: on \: both \: sides) \\ AC = 2.5 \\ \\ length \: of \: AC = 2.5m \\ \\ length \: of \: the \: diagonl \: AC \: of \: the \: rectangle \: ABCD \: = 2.5m$

Therefore,
the length of the diagonal of the rectangle=2.5m