Question

find the length of diagonal of a rectangle whose side measure 7 and and 20 cm​

Answer 1

Answer:

Diagonal of rectangle=√l²+b²

=√7²+20²

=√449

= 21.189 cm

Answer 2

$The \: length \: of \: diagonal = \sqrt{449} = 21.19 \: \: \: near \: about$

Step-by-step explanation:

Given:-

• Length of rectangle = Base = 20 cm
• Breadth of rectangle = Perpendicular = 7 cm

To Find:-

• Length of Diagonal (Hypotenuse)

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By Pythagoras Theorem

${(Hypotenuse)}^{2} = {(Base)}^{2} + {(Perpendicular)}^{2} \\ \\ = = > \: \: \:{(Hypotenuse)}^{2} = {20}^{2} + {7}^{2} \\ \\ = = > \: \: \: {(Hypotenuse)}^{2} =400 + 49 \\ \\ = = > \: \: \: {(Hypotenuse)}^{2} =449 \\ \\ Taking \: square \: root \: on \: both \: sides \\ \\ = = > \: \: \: \sqrt{{(Hypotenuse)}^{2} =} = \sqrt{449} \\ \\ = = > \: \: \: Hypotenuse = \sqrt{449} = 21.19 \: \: \: near \: about$

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