Question

find the length of diagonal of a rectangle.whose sides are of length 15 cm and 20 cm ​

Answer 1

Answer :AC is a diagonal

AB =15 cm

Bc=20cm

By using Pythagoras theorem

AC (sq.)=Bc (sq.) +AB(sq.)

AC(sq.)=15(sq.)+20(sq.)

AC(sq.)=125+400

AC(sq.)=525

AC. =√525

AC=25cm

Hence, Diagonal is 25cm

Hope it helps you

Answer 2

Answer:

let ABCD is a rectangle

and AC &BD are two diagonal

rectangle make an angle which is 90

so,

use Pythagoras theorem

${(ac) }^{2} = {(ab)}^{2} + {(bc)}^{2}$

${ac}^{2} = {15}^{2} + {20}^{2}$

$ac = \sqrt{225 + 400 } \\ ac = \sqrt{625 } \\ ac = 25$

then

diagonals of rectangle are equal

AC=25CM

hope you understand

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