find the length of diagonal of a square whose area is 2500 m square give an answer in terms of root 2
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AREA = 2500m^2
AREA = SIDE * SIDE = 2500
SIDE ^2 = 2500
SIDE = 50 m
Diagonal = 50√2
HERE UR ANSWER...
AREA = 2500m^2
AREA = SIDE * SIDE = 2500
SIDE ^2 = 2500
SIDE = 50 m
Diagonal = 50√2
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Area of square = a^2
2500 = a^2
50 = a
When we draw diagonal each part of square becomes a right angled triangle with diagonal as hypotenuse.
Diagonal^2 = a^2+a^2
Diagonal^2 = 50^2+50^2
Diagonal^2 = 2500+2500
Diagonal^2 = 5000
Diagonal = √5000
Diagonal = √(2×2×2×5×5×5×5)
Diagonal = 2×5×5×√2
Diagonal = 50√2
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2500 = a^2
50 = a
When we draw diagonal each part of square becomes a right angled triangle with diagonal as hypotenuse.
Diagonal^2 = a^2+a^2
Diagonal^2 = 50^2+50^2
Diagonal^2 = 2500+2500
Diagonal^2 = 5000
Diagonal = √5000
Diagonal = √(2×2×2×5×5×5×5)
Diagonal = 2×5×5×√2
Diagonal = 50√2
If you satisfied mark it brainliest.
Your support is encouragement for us.
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