Question

find the
length of diagonal of rectangle whose length is 12cm and breadth is 5cm

Answer 1

as due to diagonal there will be a right angled triangle and according to phythagoreas theroem
diagonal will be the hypotenuse
h²=12²+5²
h²=144+25
h²=169
h=13cm
Therefore,the diagonal of the rectangle would be 13cm
LHS= tan(A) + tan(A+60) - tan(60-A)= tan(x) + (tan(x) + tan(60))/(1 - tan(x)tan(60)) - (tan 60 - tan(A))/(1 + tan60tan(A))= tan(x) + (tan(x) + tan(60))/(1 - tan(x)tan(60)) + (tan A - tan 60)/(1 + tan60tan(A))= tan(x) + (tan(x) + √3)/(1 - √3tan(x)) + (tan(x) - √3)/(1 + √3tan(x))= tan(x) + (tan(x) - √3)/(1 + √3tan(x)) + (tan(x) + √3)/(1 - √3tan(x))= tan(x) + [(tan(x) - √3)(1 - √3tan(x)) + (tan(x) + √3)(1 + √3tan(x))]/(1-3tan²(x))= tan(x) + [tan(x) - √3tan²(x) - √3 + 3tan(x) + tan(x) + √3tan²(x) + √3 + 3tan(x)]/(1-3tan²(x))= tan(x) + 8tan(x)/(1-3tan²(x))= (tan(x) - 3tan³(x) + 8tan(x))/(1-3tan²(x))= (9tan(x) - 3tan³(x))/(1-3tan²(x))= 3(3tan(x) - tan³(x))/(1-3tan²(x))= 3tan(3x)= RHS

Answer 2

using a Pythagoras Theron.
12°+8°=x°
144+64 = √208
d = √208