Question

find the length of diognals of given squares.​

Answer 1

Answer:

The answer is $10\sqrt 2$

Step-by-step explanation:

Consider triangle QRS

$\Rightarrow$ QR $=10$ cm and RS $=10$ cm

(Since PQRS is a square)

Also QRS is a right angled triangle, so using Pythagoras

We have $\text{QR}^2+\text{RS}^2=\text{QS}^2$

              $\Rightarrow 10^2+10^2=\text{QS}^2\\\Rightarrow 200=\text{QS}^2\\\Rightarrow \text{QS}=\sqrt {200}=\sqrt {100}\times \sqrt 2=10\sqrt 2=\text{diagonal}$

(Note : If side length of a square is a, then length of its diagonal is $\sqrt 2a$)