Question

find the length of each side of the following square.​

Answer 1

Answer:

OJ = 6cm

Therefore, JL = 6 x 2 cm = 12cm.

Let each side be x

Therefore, by Pythagoras Theorem,

x² + x² = 12²

or, 2x² = 144

or, x² = 72

or, x = √72

or, x = 6√2. (Answer)

Step-by-step explanation:

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Answer 2

Answer:

since O is the mid point of both diagonals KI and JL.

so the length of diagonal KI=6+6=12cm

Also, length of diagonal JL= 12cm [diagonals of a

square are equal]

Also, every square is a rhombus.

So, area of rhombus= area of square.

1/2×KI×JL= side×side

1/2×144= (side)^2

72= (side)^2

side=√72

side=6√2cm.

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