find the length of EC from the given figure
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Given : DE || AC , DF || AE
BF = 4 , BE = 2
To Find : Length of CE
Solution:
in ΔABE
DF || AE
Using BPT ( Thales theorem )
=> AD/DB = EF/BF
=> AD/DB = 2/4
=> AD/DB = 1/2
in ΔABC
DE || AC
AD/DB = CE/BE
=> 1/2 = CE/( BF + FE)
=> 1/2 = CE/ ( 4 + 2)
=> 1/2 = CE/6
=> CE = 3
Length of CE = 3
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