Find the length of hypotenuse of the following right angled triangles
a. △ABC, AB=6CM, BC=8CM, angle B=90 degrees
b. Angle X=90 degrees , XZ=4CM, XY=3CM,
c. Angle B=90 degrees , AB=12CM, BC=5CM,
Answers
Answered by
2
AB=6
3
cm
AC=12cm
BC=6cm
Solution:
AC
2
=144
AB
2
=108
BC
2
=36
Since,
AC
2
=AB
2
+BC
2
∴ By Converse of Pythagoras Theorem,
△ABC is an Right Angle Triangle at B.
∴∠B=90
o
ABC is a triangle , in which ∠ B = 90 °
AB = 12 cm , BC = 5 cm
BC is the base of the Δ ABC
AB is the perpendicular of Δ ABC
AC is the hypotenuse of Δ ABC
We have to find AC, using Pythagoras theorem
H ² = P ² + B ²
AC ² = 12 ² + 5 ²
AC ² = 144 + 25
AC ² = 169
AC = √ 169
AC = 13
So, the hypotenuse is 13 cm
Hypotenuse is the circumradius of triangle
Answered by
1
Answer:
a. 10
b. 5
c. 13
Step-by-step explanation:
by Pythagoras theorem this question becomes easy. enjoy
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