Question

find the
length of hypotenuse of
the triangle who base - 5 cm
and S. said - 12 cm​

Answer 1

Answer:

By Pythagoras Theorem

(H)^2 = (P)^2 + (B)^2

(H)^2 = (12)^2 + (5)^2

(H)^2 = 144 + 25

(H)^2 = 169

H = 13

Answer 2

Question :-

• Find the length of hypotenuse of the triangle who's base is 5 cm and perpendicular is 12 cm.

Answer :-

• The length of the hypotenuse is 13 cm.

Given :-

• Base = 5 cm.
• Perpendicular = 12 cm.

To find :-

• The length of the hypotenuse.

Step-by-step explanation :-

• In this question, the measure of the base and perpendicular has been given to us. We have to find the hypotenuse. It is a right angled triangle. So let's use the Pythagoras theorem to find out our answer.

• Pythagoras theorem :- In a right angled triangle, the sum of squares of two other sides is equal to the hypotenuse.

Calculations :-

• Let the hypotenuse be x.

Here,

• The other two sides are 5 cm and 12 cm.

Now, applying the Pythagoras theorem,

$\sf \implies {x}^{2} = {5}^{2} + {12}^{2}$

$\sf\implies {x}^{2} = 25 + 144$

$\sf\implies {x}^{2} = 169$

$\sf \implies x = \sqrt{169}$

$\underline{\boxed{\sf \implies x = 13.}}$

• x = 13.

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• Hence, the hypotenuse = 13 cm.