find the length of median CD of the triangle abc, whose vertices are A(6,8),B(-4,2),C(5,-1)
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Given : Median CD of the triangle abc, whose vertices are A(6,8), B(-4,2), C(5,-1)
To Find : length of median CD
Solution:
A(6,8), B(-4,2), C(5,-1)
CD is Median
Hence D is mid point of AB
D = (6 -4 )/2 , (8 + 2)/2
=> D = ( 1 , 5)
C = *( 5 , - 1)
D = ( 1, 5)
Length of CD = √(5 - 1)² + (-1 - 5)²
= √16 + 36
= √52
= 2√13
= 7.21
length of median CD = 2√13 = 7.21
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