Question

find the length of perpendicular drawn from the point P(1,3,5) on y-axis.​

Answer 1

Answer:

√26 or 5.099 (approx.)

Step-by-step explanation:

As we know that:

on the y-axis, x=0 and z=0

∴ Point A = (0,3,0)

∴ PA = √(0-1)²+(3-3)²+(0-5)²

        = √1+0+25

        = √26 or 5.099 (approx.)

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i hope it will helps you friend

Answer 2

The length of perpendicular drawn from the point P(1,3,5) on y-axis is $\sqrt{26}$.

Step-by-step explanation:

The given point is P(1,3,5).

We need to find the length of perpendicular drawn from the point P(1,3,5) on y-axis.

At y-axis, x and z coordinates are 0 and y-coordinate is same as point P(1,3,5). So, the point on y-axis is (0,3,0).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_1-z_2)^2}$

The distance between (0,3,0) and (1,3,5) is

$d=\sqrt{(1-0)^2+(3-3)^2+(5-0)^2}$

$d=\sqrt{1+0+25}$

$d=\sqrt{26}$

Therefore, the length of perpendicular drawn from the point P(1,3,5) on y-axis is $\sqrt{26}$.

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