Math, asked by gadharikeshav00, 9 months ago

find the length of perpendicularfrm(3.2)on the line 4x-6y-5=0​

Answers

Answered by guna18
2

Answer:

5 \div  \sqrt{52}

Step-by-step explanation:

hope it will help u

Attachments:
Answered by pulakmath007
0

The length of perpendicular from (3, 2) on the line 4x - 6y - 5 = 0 is 5/52 unit

Given :

The line 4x - 6y - 5 = 0

To find :

The length of perpendicular from (3, 2) on the line 4x - 6y - 5 = 0

Solution :

Step 1 of 2 :

Write down the given equation of the line

The given equation of the line is

4x - 6y - 5 = 0

Step 2 of 2 :

Find length of the perpendicular

The length of perpendicular from (3, 2) on the line 4x - 6y - 5 = 0

\displaystyle \sf{ =   \bigg|  \frac{(4 \times 3) - ( 6 \times 2) - 5}{ \sqrt{ {4}^{2}  +  {( - 6)}^{2} } } \bigg|   \:  \:  \: unit }

\displaystyle \sf{ =   \bigg|  \frac{12 - 12 - 5}{ \sqrt{ 16 + 36} } \bigg|   \:  \:  \: unit }

\displaystyle \sf{ =   \bigg|  \frac{ - 5}{ \sqrt{ 52} } \bigg|   \:  \:  \: unit }

\displaystyle \sf{ =    \frac{5}{ \sqrt{52} }   \:  \:  \: unit }

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