Find the length of QR in Figure 9
Attachments:

Answers
Answered by
0
Answer:
14cm
Step-by-step explanation:
Step 1
Using Pythagoras find PT (altitude) for triangle PTR
PT =
= 12.
Step 2
For triangle PQT which is also a right angled traingle again use Pythagoras to find QT.
QT =
= 9
Step 3
Finally add QT and RT to get QR
= 9 + 5
= 14cm
Answered by
0
♣ In ∆PTR , right angled at T.
By Pythagoras theorem,
Hypotenuse² = base² + height²
➛ 13² = 5² + PT²
➛ PT² = 13² - 5²
➛ PT² = 169 - 25
➛ PT² = 144
➛ PT = 12cm
▬▬▬▬▬▬▬▬▬▬▬▬
Now , ♣
In ∆PTQ ,
By Pythagoras theorem,
➛ QP² = QT² + PT²
➛ 15² = QT² + 12²
➛ QT² = 15² - 12²
➛ QT² = 225 - 144
➛ QT² = 81
➛ QT = 9cm
From figure ,
➠ QR = QT + TR
➠ QR = 9 + 5
➠ QR = 14cm
Hence , QR = 14cm
Similar questions