Math, asked by ImmaYeetYourPizza, 2 days ago

Find the length of rectangle whose perimeter is 28 cm and breadth is 5 cm

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Answered by krishnanshi3950
3

Answer:

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Answered by Anonymous
80

Given : Perimeter of a Rectangle is 28 cm and its Breadth is 5 cm .

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To Find : Find the Length of Rectangle

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SolutioN : For Calculating the length of Rectangle let's apply the formula of Perimeter of Rectangle . Let's Solve :

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 \maltese Formula Used :

  •  {\underline{\boxed{\pmb{\sf{ Perimeter = 2 \bigg( Length + Breadth \bigg) }}}}}

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 \maltese Calculating the Length :

 \begin{gathered} \qquad \; \longrightarrow \; \; \sf { Perimeter = 2 \bigg( L + B \bigg) } \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \longrightarrow \; \; \sf { 28 = 2 \bigg( L + 5 \bigg) } \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \longrightarrow \; \; \sf { 28 = 2L + 10 } \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \longrightarrow \; \; \sf { 28 - 10 = 2L } \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \longrightarrow \; \; \sf { 18 = 2L } \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \longrightarrow \; \; \sf { \dfrac{18}{2} = L } \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \longrightarrow \; \; \sf { \cancel\dfrac{18}{2} = L } \\ \\ \\ \end{gathered}

 \begin{gathered} \qquad \; \longrightarrow \; \; {\underline{\boxed{\pmb{\sf{ Length = 9 \; cm }}}}} \; {\red{\bigstar}} \\ \\ \\ \end{gathered}

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 \therefore \; Length of the Rectangle is 9 cm .

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