find the length of right angled triangle with a hypotenuse 40 cm And one of the other two sides 24 cm
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by Pythagoras theorem
h²=p²+b²
b²=h²-p²
b=√40²-24²=√1600-576=√1024=32
so,
the third side is 32 cm long
h²=p²+b²
b²=h²-p²
b=√40²-24²=√1600-576=√1024=32
so,
the third side is 32 cm long
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Answer:
Find the area of a triangles whose vertices are ( -3, 1) , ( 1, -3) and ( 2,3 )
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