Question

Find the length of second diagonal ofa rhombus whose area is 12x*x*y*y*y cmsq. and d1=3xy

Answer 1

Step-by-step explanation:

We know that,

area of rhombus =1/2*D1*d2

Therefore,

$12 \times x \times x \times y \times y \times y = \\ \frac{1}{2} \times 3xy \times d2$

$d2 = \frac{2 \times 12 \times x \times x \times y \times y \times y}{3 \times x \times y }$

$d2 = 8 \times x \times y \times y \\ = 8x {y}^{2}$

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