Question

Find the length of second pendulum at a place where g=10 m/s².​

Answer 1

Answer:

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Explanation:

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Answer 2

Given :-

• g = 10m/s^2

To find :-

• Length of 2nd pendulum = ?

Solution :-

We know that the time required for 1 oscillation is 2 sec

So ,  T = 2π(√l/g)

Now ,

T² = 4π²(l/g)

= 40/4 * 3.14²

= 40/39.43

= 1.01m

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