Find the length of shorter diagonal of a rhombus having sides 10cm and one pair of opposite angle to the
shorter diagonal is 30° (round off to the nearest integer).
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The rhombus has sides of 10 cm and one angle = 60 deg. It means the rhombus is composed of two equilateral triangles with a common side. So the shorter diagonal of the rhombus = 10 cm. The longer diagonal = 2*10 cos 30 = 17.32 cm.
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