find the length of side and perimeter of an equilateral triangle whose height is root 3 cm
Answers
Answered by
208
Let ∆ ABC is equilateral triangle.
Seg AD is median.
Therefore in ∆ ABC,
Angle A=30 (as AD is median)
Angle B=90(as AD is median)
Angle C=60(as ∆ABC is equilateral triangle)
Therefore by 30-60-90 theorem.
AD=✓3/2 ×AC
✓3 = ✓3/2 × AC
✓3×2/✓3 = AC
Therefore 2cm = AC
it is equilateral triangle
Therefore perimeter=3×side
=3×2cm
= 6cm
Seg AD is median.
Therefore in ∆ ABC,
Angle A=30 (as AD is median)
Angle B=90(as AD is median)
Angle C=60(as ∆ABC is equilateral triangle)
Therefore by 30-60-90 theorem.
AD=✓3/2 ×AC
✓3 = ✓3/2 × AC
✓3×2/✓3 = AC
Therefore 2cm = AC
it is equilateral triangle
Therefore perimeter=3×side
=3×2cm
= 6cm
Answered by
85
Hey there!
Given,
Altitude = √3 cm
Let the ΔABC be equilateral triangle.
All angles will be 60°.
And Altitude (AD) will bisect the base.
So, ∠ADC = 90°.
Let the side be a. Then, by pythagoras theorem in ΔADC,
Altitude² + (a/2)² = a²
3² = a²- a²/4
3 = 3a²/4
a² = 4
a = 2 cm
Now,
Perimeter = 3 * side
= 3 * 2 cm
= 6 cm
Hope It Helps You!
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