Find the length of side of the square .if the length of the diagonal is 10 cm?
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square ABCD has diagonal BD=10 cm
here,∆BCD is a right triangle I.e. angle C =90°
now,by PGT
BD^2=DC^2+BC^2
10^2=DC^2+DC^2. (BC=DC)
100=2×DC^2
DC^2=50
DC=√50
therefore
AB=BC=CD=AD=5√2cm
here,∆BCD is a right triangle I.e. angle C =90°
now,by PGT
BD^2=DC^2+BC^2
10^2=DC^2+DC^2. (BC=DC)
100=2×DC^2
DC^2=50
DC=√50
therefore
AB=BC=CD=AD=5√2cm
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