Question

find the length of simple pendulum which complete 6 oxilation in 30 seconds Take g = 9.8 m/s^2 and pie

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Answer 1

Explanation:

Time taken for oscillations = 1.8 s

Frequency = 6/1.8 Hz

= 3.33 Hz

Time Period = 1/F

= [1/3.33] s

= 0.3 s

Length of Simple Pendulum = Time Period = 2T √l/g

= 0.3 = 2*3.14* √l/9.8

= 0.3 = 6.28 * √I/9.8

= 0.3/6.28 = √I/9.8

= (0.3)²/(6.28)² = 1/9.8

= [(0.3)² * 9.8] / (6.28)² = |

= [0.09*9.8] / 39.43 = |

= 0.882/39.43 = |

= 0.022 m = |

or,

= 2.2 cm = 1