find the length of sub tangent
on the curvey=bsine a
at a point
point on the
NOC
SX)
Answers
Answer:
A line can be called a tangent to the differentiable curve, y = f(x) at a point P if it makes an angle Θ at the x-axis. The derivative dy / dx = tan Θ is the slope of the tangent to the curve at a point.
Step-by-step explanation:
Equation of normal at (x1, y1) is y-y_{1} = \frac{-1}{\frac{dy}{dx}} (x-x_{1})y−y
1
=
dx
dy
−1
(x−x
1
)
where the slope is calculated at the point (x, y).
The slope of the tangent of the curve is given by the derivative of the curve equation with respect to x.
The slope of the normal is given by \frac{-1}{\frac{dy}{dx}} (x_1, y_1)
dx
dy
−1
(x
1
,y
1
).
The tangent equation is given by (y – b) = \frac{-dx}{dy} (x-a)
dy
−dx
(x−a).
If x2 + y2 + 2gx + 2fy + c = 0 is a circle and a point is taken outside the circle such that a line drawn from the point to proceed through the boundary of a circle by coming in contact with the tangency point is given by, y-(-f)=m(x-[-g]*\sqrt{1+m^2})y−(−f)=m(x−[−g]∗
1+m
2
)
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