find the length of tangent segment from a point. which is at a distance of 5 cm from the centre of the circle with radius 3 cm .
Answers
Answered by
12
Hey friend your is here
Given: PQ is a tangent to the circle intersect at Q. OP = 5 cm and OQ = 3 cm.
To find: PQ
Proof:
In rt.△ OQP, by Pythagoras theorem
PQ =4
Therefore the length of the tangent from a point is 4 cm.
Given: PQ is a tangent to the circle intersect at Q. OP = 5 cm and OQ = 3 cm.
To find: PQ
Proof:
In rt.△ OQP, by Pythagoras theorem
PQ =4
Therefore the length of the tangent from a point is 4 cm.
Answered by
16
Heya Frnd ..........☺
Distance of the point from center = 5 cm
Radius = 3 cm
reqd. distance = x
Now,
Tangent forms 90° at the center thus forming a right < ∆.
Therefore ,
5² = x² + 3²
25 - 9 =x²
So,
x = √16
x = 4 cm
So,
The reqd. distance is 4 cm.
_____☺☺☺_____
HOPE IT WILL HELP YOU............
Distance of the point from center = 5 cm
Radius = 3 cm
reqd. distance = x
Now,
Tangent forms 90° at the center thus forming a right < ∆.
Therefore ,
5² = x² + 3²
25 - 9 =x²
So,
x = √16
x = 4 cm
So,
The reqd. distance is 4 cm.
_____☺☺☺_____
HOPE IT WILL HELP YOU............
Similar questions