find the length of tangent to the circle with centre o and radius 6 cm from a point p such that op = 10 CM
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Answer:
hope u will like my answer
Step-by-step explanation:
here,o is centre and let oq be perpendicular to the tangent op.so oq=6cm=radius and op=10cm.
by Pythagoras theorem,
(op)2=(oq)2+(qp)2
(10)2=(6)2+(qp)2
100=36+(qp)2
100-36=(qp)2
qp2=64
qp = \sqrt{64}qp=
64
qp=8cm
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