Question

Find the length of the 3 m wide canvas required to make a conical tent of base radius
9 m and height 12 m (use π = 3.14).

Answer 1

Answer:

Given : Height (h) = 8m

Radius (r) = 6m

According to Pythagoras theorem,

l² = r² + h²

l² = (6² + 8²)

l² = 36 + 64

l² = 100

l = √100 = 10 m

Therefore, slant height of the conical tent = 10 m.

CSA of conical tent = πrl

= π × 6m × 10m

= 3.14 × 6m × 10m

= 188.4 m2

Now, Let the length of tarpaulin sheet required be "x" m

As 20 cm will be wasted, therefore, the effective length will be = (x − 20 cm) = (x − 0.2 m)

Breadth of tarpaulin = 3 m

Area of sheet = CSA of tent

[(x − 0.2 m) × 3] m = 188.4 m2

x − 0.2 m = 62.8 m

x = 63 m

Therefore, the length of the required tarpaulin sheet will be 63 m.