Question

Find the length of the altitude of an equilateral triangle of side 5‚àö3cm

Answer 1

By Pythagoras theorem,


$5^2 = height^2 + (5/2)^2$


25 = $height + \frac{25}{4}$


25 - $\frac{25}{4}$ = $height^2$


$\frac{100 - 25}{4}$ = height²


$\frac{75}{4}$ = height²


$\sqrt{ \frac{75}{4} }$ = height 




i hope this will help you



-by ABHAY