Question

Find the length of the altitudes from the vertices of triangle whose vertices are (-1,1) (5,2) and(3,-1)

Answer 1

Refer The Attachment ⬆️

Length of the Altitude $\longmapsto\;{\Large{\bold{\frac{16}{\sqrt{13}}}}}\;\bold{units}$

$\boxed{\sf{Area\;of\; Triangle = \frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|}}$

$\boxed{\sf{Area\;of\; Triangle = \frac{1}{2}×Base×Height}}$

$\boxed{\sf{Length\; between\;two\; points = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}}}$

$\tt{@MrMonarque}$

Hope It Helps You ✌️