Question

find the length of the arc cut off from circle of radius is 12cm by a chord 12cm long also find the area of the minor segment ( take π = 3.14 and √3 = 1.732 )​ take AO = 12 cm and AP = 12 cm and angle O is 60 degree

Answer 1

Answer:

given a circle of radius 12 cm.

OA=OB=12 cm= radius of the circle and .Let AB be the chord of 12 cm. hence we get an equilateral triangle OAB inside the circle that means ∠O=∠A=∠B=60o to find the length of the arcs (APB and ADB) of circle. 

circumference of the circle =2πr=2π×12 length of the arc APB of the circle =3602π×12×60

=3602π×12×60=4π=12.56 cm

Now the length of the arc AQB=3602π×12×(360−60)

=3602π×12×300=20π

=62.80 cm

Now to find the Area of the minor segment

= Area of the sector ABCA= Area of the sector AOBCA

= Area of the triangle OAB

Area of the sector AOBCA=π×(12)2×36060

=π×12×2=24π=75.36 cm2

Area of the triangle OAB =43×12×12=363

Answer 2

Step-by-step explanation:

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