Question

find the length of the chord 6 cm away from the centre a circle of radius 10 cm​

Answer 1

Step-by-step explanation:

O is the centre of circle, radius of the circle=OA=r=10 cm, AB = ?, OC = 6 cm, C is point on chord AB & OC perpendicular to AB.

Now, In right triangle OAC,

By Pythagoras Theorem

OA ² = AC² + CO²

Or, AC² = OA² - CO²

Or, AC² = 10² - 6² = 100 - 36 = 64

Or, AC² = 100 - 36

Or, AC² = 64

Or, AC² = 8²

Or, AC = 8

Or AB = AC + CB

Or AB = 8 + 8 ----------- (AC = CB)

Or AB = 16 cm

Therefore, length of chord = AB = 16 cm