find the length of the chord which is at a distance of 10 cm from the centre of a circle of rodius 11 cm
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Answered by
1
Answer:
As we all know the chord=Diameter
r=11cm
d= r×2
d=11×2
d=22cm Ans
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Answered by
1
Answer:
See the attached figure...
Step-by-step explanation:
Radius OA = OB = 11cm
Distance OM = 10cm
From ∆AMO,
AO² = OM² + AM²
=> 11² = 10² + AM²
=> AM² = 121 - 100
=> AM = √21 cm
Similarly, BM = √21cm
AB = AM + BM
= √21 + √21
= 2√21 cm
Therefore, the chord AB is 2√21 cm long.
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