Find the length of the chord which is at distance of 4cm from the centre of a circle of radius 5cm
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the chord of a circle (PQ)=?
distance of the chord from the centre(OR)=4cm
radius of the circle(OP)=5cm
By Pythagoras theorem,
OPsq.=OR sq.+PR sq.
5sq.=4 sq.+PR sq.
25 =16 +PR. sq.
PR sq.=25-16
PR sq. =9cm
therefore PR=3cm
PR +QR=3+3= 6cm(the perpendicular drawn from centre to chord bisects the chord.
therefore length of the chord is 6 cm
distance of the chord from the centre(OR)=4cm
radius of the circle(OP)=5cm
By Pythagoras theorem,
OPsq.=OR sq.+PR sq.
5sq.=4 sq.+PR sq.
25 =16 +PR. sq.
PR sq.=25-16
PR sq. =9cm
therefore PR=3cm
PR +QR=3+3= 6cm(the perpendicular drawn from centre to chord bisects the chord.
therefore length of the chord is 6 cm
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Answer is 6 cm
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