Question

find the length of the cord which is at the distance of 3cm from the centre of a circle of radius 5cm​

Answer 1

Answer:

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Given radius (r)=5cm

and let BAC is the chord. Midpoint is B

perpendicular from centre to chord (OA)=3cm

then BA=(√(5²-3²)=√16=4cm

length of chord (BAC)=2BA because BA=AC

length of chord (BAC)=2*4=8cm

Step-by-step explanation:

Answer 2

Answer:

By pythogoras theoram,

let AB be the chord of the circle

P is the mid point of the chord

OP=3cm

OB=5cm

PB×PB=OB×OB-OP×OP

=5×5-3×3

=25-9

=16

PB×PB =4×4

PB=4CM

THEN,AB=2(PB)

=2×4=8

then chord of the circle will be 8 cm