Question

find the length of the diagonal in the cuboid of dimensions (11 x 10 x 2) cm​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer :-

• Diagonal of cuboid = 15 cm

Given :-

• Length of cuboid = 11 cm
• Width of cuboid = 10 cm
• Height of cuboid = 2 cm

To Find :-

• Diagonal of cuboid = ?

Explanation :-

As we know, we have formulae to find the diagonal of cuboid .

$\blue { \boxed { \bf \bigstar \; Diagonal \; of \; Cuboid = \sqrt{(L)^2+(B)^2+(H)^2} \; \; \bigstar }}$

$\rm : \; \longmapsto \sqrt{(11)^2+(10)^2+(2)^2} \; \; \; cm$

$\rm : \; \longmapsto \sqrt{(121)+(100)+(4)} \; \; \; cm$

$\rm : \; \longmapsto \sqrt{(221)+(4)} \; \; \; cm$

$\rm : \; \longmapsto \sqrt{(204)} \; \; \; cm$

$\rm : \; \longmapsto \sqrt{225} \; \; \; cm$

$\green { \underline { \boxed { \bf : \; \longmapsto 15 \; \; \; cm}}}$

Hence, the diagonal of the of the cuboid is 15 cm.

$\huge \text{\underline{\underline{More To Know}}}$

$\rm \star \; Diagonal \; of \; Cuboid = \sqrt{(L)^2+(B)^2+(H)^2}$

$\rm \star \; Diagonal \; of \; Cube = \sqrt{3} \; (Side)$

$\rm \star \; TSA \; of \; Cuboid = 2 \; (LB+BH+HL)$

$\rm \star \; TSA \; of \; Cube = 6(Side)^2$

$\rm \star \; LSA \; of \; Cuboid = 2H\; (L+B)$

$\rm \star \; LSA \; of \; Cube = 4(Side)^2$