Question

find the length of the diagonal of a rectangle whose breath and length are 6cm and 8cm, respectively
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Answer 1

Given :

• Length of the rectangle = 8 cm
• Breadth of the rectangle = 6 cm

To Find :

• The diagonal of the rectangle

Solution :

$\\ \\ \textsf{Length of the rectangle = 8 cm} \\ \\ \textsf{Breadth of the rectangle = 6 cm} \\ \\ \therefore \: \: \: \: \textsf{Diagonal of the rectangle =} \: \tt {\sqrt{ {l}^{2} + {b}^{2} } } \: cm\\ \\ \: \: \: \: \: \: \: \: \textsf{Diagonal of the rectangle =} \: \tt {\sqrt{ {8}^{2} + {6}^{2} } } \: cm \\ \\ \: \: \: \: \: \: \: \: \textsf{Diagonal of the rectangle =} \: \tt {\sqrt{ 64 + 36 } } \: cm\\ \\ \textsf{Diagonal of the rectangle =} \: \tt {\sqrt{ 100\: cm} } \\ \\ \textsf{Diagonal of the rectangle =} \: \tt 10 \: cm \:\: \:\:$

Hence, the length of the diagonal of the rectangle is 10 cm.

Answer 2

As per the data given in the question,

We have to determine the value of length of diagonal of rectangle.

As per question,

It is given that,

Length and breadth of rectangle = 6 cm and 8 cm.

As we know that,

A rectangle is a type of quadrilateral having equal opposite sides.

While, diagonal of the rectangle is a straight line drawn from the one corner of rectangle to the opposite corner of rectangle.

So, Length of Diagonal of a rectangle can be determined by using the below mentioned formula,

$= \sqrt{l^{2} + b^{2} }\\= \sqrt{6^{2}+ 8^{2} }\\= \sqrt{36+64}\\= \sqrt{100}\\= 10 \:cm$