find the length of the diagonal of a rectangle whose length is 15 cm and breadth is 8 cm and find it's perimeter
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Length of the Rectangle = 15 cm
Breadth of the Rectangle = 8 cm
The measure of the diagonal
Perimeter of Rectangle
Refer the Attachment for better understanding.
In ∆ ACD,
• Base = CD = 15 cm
• Height = AC = 8 cm
• Hypotenuse = AD = x
By Pythagoras Theorem :
(Hypotenuse) ² = (Base)² + (Height)²
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hello...!
» The Diagonal is 17 cm.
» Perimeter is 46 cm
» Explanation «
» Given :
Length of the Rectangle = 15 cm
Breadth of the Rectangle = 8 cm
» To find :
The measure of the diagonal ›
Perimeter of Rectangle
Solution :
Refer the Attachment for better understanding.
In ∆ ACD,
• Base = CD = 15 cm
• Height = AC = 8 cm
• Hypotenuse = AD = x
By Pythagoras Theorem :
(Hypotenuse) ² = (Base)² + (Height)²
» x² = 15²+ 8²
» x² = 225 + 64
» x²=289
» x=17
hypotenuse=17cm
★Diagonal=17cm
Perimeter of the Rectangle :
» 2(length+breadth)
» {2(8 + 15)}
» 2(8+15)
» 16+30
» 46cm
★Perimeter=46cm
The Diagonal is 17 cm.
Perimeter is 46 cm
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