Question

find the length of the diagonal of a rectangle whose sides are 15cm and 8cm​

Answer 1

Answer:

Length=15cmand breadth=8cm

Lenght of diagonal=\sqrt{l^2+b^2

therfore=\sqrt{ 15^2+8^2

=\sqrt{289 =17

Therfore length of the diagonal =17

Answer 2

The diagonal of rectangle is equal to 17cm.

Step-by-step explanation:

We are given a rectangle having length and breadth as 15 and 8 cm respectively and we have to find the diagonal of this rectangle.

• Formula used,

We use Pythagoras theorem here to find the diagonal of rectangle.

$H^{2} =P^{2} +B^{2}$

$H=\sqrt{P^{2} +B^{2} }$

H is for hypotenuse, P is for perpendicular and B is for base of right angled triangle.

• Calculation for diagonal of rectangle

A rectangle have,

length $=15cm$

Breadth$=8cm$

diagonal in rectangle is just like a Hypotenuse of a right angled triangle because all angles of rectangle are of $90\°$and Length and breadth are the base and perpendicular respectively of right angled triangle.

so now we have,

$P=8cm$

$B=15cm$

and we have to find H.

using formula,

$H=\sqrt{P^{2} +B^{2} }$

   $=\sqrt{(5)^{2} +(15)^{2} }$

   $=\sqrt{64+225}$

   $=\sqrt{289}$

   $=17cm$

we get the hypotenuse as diagonal of rectangle is $17cm$.

So the answer of this question as the diagonal of rectangle is $17cm$.