find the length of the diagonal of a square of side 8cm
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diagonal of square = side root 2
u can find further by putting values
u can find further by putting values
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Since the length of each side of the square = 8cm.
So now when a diagonal of the square is drawn so the square gets divided up in two right angled triangle,
Diagonal^2 = Side^2 + Side^2
Diagonal^2 = 8^2 + 8^2
Diagonal^2 = 64 + 64
Diagonal = root of 128
Diagonal = 8root2
So now when a diagonal of the square is drawn so the square gets divided up in two right angled triangle,
Diagonal^2 = Side^2 + Side^2
Diagonal^2 = 8^2 + 8^2
Diagonal^2 = 64 + 64
Diagonal = root of 128
Diagonal = 8root2
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