Question

Find the length of the diagonal of rectangle whose length is 8 and width is 6

Answer 1

Given:
Length= 8

Breadth= 6

diagonal of rectangle =√ length ²+ breadth ²

diagonal of rectangle= √8²+6²

diagonal of rectangle=√ 64+36

diagonal of rectangle= √100 = 10

Diagonal of rectangle = 10

Answer 2

Let us consider a rectangle ABCD with a diagonal AC.

Here, diagonal divided rectangle into 2 right triangles (∆ABC and ∆ACD)

Take any one of two triangles

Let us take ∆ABC,

Here, AB=base of triangle=length of rectangle=8 cm

BC=Height of triangle=width of rectangle=6cm

AC=Hypotenuse of triangle=diagonal of rectangle=?

So, we have to.find hypotenuse of the obtained triangle.

We know that, in a right triangle,

(Hypotenuse)²=(Base)²+(height)²
(Hypotenuse)=√(B)²+(H)²
AC=√(AB)²+(BC)²

By substituting values,

AC=√(8)²+(6)²
AC=√64+36
AC=√100
AC=√10×10
AC=10 cm

So, diagonal of rectangle is 10 cm